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Is there a limit on CCA for my b2?


jkufen

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I just got my new battery today for the winch today and was curious if there is a limit on how many CCA my factory b2 can take. The battery I got is rated at 950 CCA and I don't want to burn anything up. Right now that battery is going to be for the winch but I am wanting to get one to power the lights and starting. At $40 a pop I can afford to get the extra battery. My buddy gets them at cost and that's what he charges me for a $200 battery! To start out with for temporary use I am just going to mount the battery under the hood and hook the winch to it. I will keep the battery separate and after I use the winch I was gonna run alligator clips from the starting battery to this battery so that it is charged just not under a load. I am hoping this will get me through my trip to Gulches ORV Park in 2 weeks then I can come back and add another alternator or a more powerful one. I believe the alternator I have now puts off 110 amps but I know it is not the one that is listed for it at the parts store. Anyways I guess my question is can I use one of these truck batteries as my starting battery? I know the whole thing about needing a deep cycle battery for this winch this is just to get me by until I am able to get the deep cycle.

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adsm08

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Not really. The various loads will only draw as much amperage as they need to run, unless there is some other problem with the circuit.

A 950 battery won't kill anything.
 

jkufen

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that is what i needed to know. Thanks
 

adsm08

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Yeah, I ran an 850 in my truck for years. The only thing to watch with high amp batteries is if the vehicle sits a lot the battery dies faster. High amp configurations sulfate and die quickly.
 

jkufen

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Well hopefully it won't sit too long
 

PetesPonies

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There is never an upper limit to anything current wise. Current cannot be forced on an electrical device. Therefore, you could add an alternator that can supply 1000 amps :) No problem. Voltage needs to be close and the other component is resistance. So unless something changed with resistance with a device, and you supply the correct voltage . . . never have a concern in regards to current ( which is Amps ).
 

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